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8 years, 11 months ago
Consider a polygon of n sidees.Find the number of triangles none of whose sides is the side of he polygon.
8 years, 11 months ago
In order to form a triangle we need n vertices. You can choose the first vertex in n ways. The second vertex can be chosen in N-3 ways. Similarly, the vertex can be chosen in N-5 ways. So the required number of ways are: N*N-3* N-5
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