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9 years, 1 month ago
9 years, 1 month ago
answer is 2^(1/6)
but how????
this is how it was solved
a^p=2a^(p+6)
=> p=2^(1/6)
9 years, 1 month ago
PQ is parallel to X-axis => y-coordinates of P and Q are same and the x-coordinates differ by 6 (as the diameter is 6).
Q is a point on y = 2a => y coordinate of both P and Q is equal to 2a units.
P is a point on y = ax => x coordinate of P is 2 units => x coordinate of Q can be either -4 or 8.
We cannot say anything about the value of a from this information. So, the value of a cannot be determined.
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