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Inequalities

Theory
  • For any positive real number, x+$$\frac{1}{x} \geq$$ 2

  • For any real number x > 1, 2 < $$(1+\frac{1}{x})^{x}$$ < 2.8.

As x increases, the function tends to an irrational number called 'e' which is approximately equal to 2.718.

    Theory

    The topic Inequalities is one of the few sections in the quantitative part which can throw up tricky questions. The questions are often asked in conjunction with other sections like ratio and proportion, progressions etc. The theory involved in Inequalities is very limited and students should be comfortable with the basics involving addition, multiplication and changing of signs of the inequalities. The scope for making an error is high in this section as a minor mistake in calculation (like forgetting the sign) can lead to a completely different answer.

    Formula
    • Wavy curve method for solving (x−a)(x−b)(x−c) > 0
    • Arrange the critical points in ascending order.
      $$a<b<c$$
    • Number line representation:


    • $$(x-a)(x-b)(x-c) > 0 \Rightarrow x \in (a,b)\cup(c,\infty)$$

    Formula
    • The modulus of x, |x| equals the maximum of x and –x
    • For any two real numbers 'a' and 'b', 

                                      |a|+|b| ≥ |a+b|
                                        |a|-|b| ≤ |a-b|                                 

                                       |a.b| = |a| |b|

    • If |x| ≤ k then the value of x lies between –k and k, or –k ≤ x ≤ k
    • If |x| ≥ k then x ≥ k or x ≤ -k
    • For any real number 'a', $$a^2$$ = $$|a|^2$$
    Formula
    • If a$$x^{2}$$+bx+c < 0 then a(x-m)(x-n) < 0.
      If a>0 and n>m, then m < x < n
      if a<0 and n>m, then x < m and x > n
    • If a$$x^{2}$$+bx+c > 0 then a(x-m)(x-n) > 0.
      If a>0 and n>m, then x < m and x > n
      if a<0 and n>m, then m < x < n
    • If a$$x^{2}$$+bx+c > 0 but m = n, then the value of x exists for all values, except x is equal to m, i.e., x < m and x > m but x ≠ m
    • If a, x, b are positive, ax > b => x > $$\dfrac{b}{a}$$ and ax < b => x < $$\dfrac{b}{a}$$
    Formula
    • For any three real numbers X, Y and Z; if X > Y then X+Z > Y+Z

    • If X > Y and

      1. Z is positive, then XZ > YZ
      2. Z is negative, then XZ < YZ
      3. If X and Y are of the same sign, $$\dfrac{1}{X}$$ < $$\dfrac{1}{Y}$$
      4. If X and Y are of different signs, $$\dfrac{1}{X}$$ > $$\dfrac{1}{Y}$$
      5. Squaring rule: If X, Y > 0 and X > Y then X² > Y² 
      6. If 0 < X < 1: X² < X < √X — behaviour of fractions under powers
      7. If X > 1: X² > X > √X
    Formula

    Prerequisites

    The logarithm $$\log_a x$$ is defined only when $$x > 0$$, $$a > 0$$ and $$a \neq 1$$.

    Before solving any logarithmic inequality, find the domain of every logarithmic expression first. Solve the inequality, then take the intersection of the solution with the domain.

    Monotonicity: The core idea

    The direction of a logarithmic inequality depends entirely on the base.

    If $$a > 1$$, then $$\log_a x$$ is an increasing function:
    $$x_1 < x_2 \iff \log_a x_1 < \log_a x_2$$
    The inequality sign is preserved.

    If $$0 < a < 1$$, then $$\log_a x$$ is a decreasing function:
    $$x_1 < x_2 \iff \log_a x_1 > \log_a x_2$$
    The inequality sign is reversed.

    Formula

    Relationship between AM, GM and HM for two numbers a and b,

    • G.M=$$\sqrt{AM \times HM}$$
    • A.M ≥ G.M ≥ H.M
    • The equality holds true if and only if all the terms are equal. (AM = GM = HM)

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