Edit MetaData
1 year, 9 months ago
1 year, 9 months ago
Hi Ryuzaki Lawliet,
Natural numbers less than 10^5 means it includes 2 digit numbers, 3 digit numbers, 4 digit numbers and maximum 5 digit numbers. Therefore, we take 5 variables
x + y + z + a + b = 10
x, y, z, a, and b can be 0 as well.
Number of ways = 10+5-1_C_5-1 = 14C4
As x, y, z, a and b are single digit numbers, they cannot take the value 10. Therefore, we need to subtract the cases where the values of x,y,x,a,b is 10. Number of such cases = 5
Number of natural numbers less than 10^5 is the sum of their digits equal to 10 = 14_C_4 - 5 = 1001 - 5 = 996
Hope this helps!
1 year, 9 months ago
Search your question in google in brainly , simple solution is mentioned, if u have doubt let me know.
Smart cracku guys are not allowing to paste answer here
Quick, Easy and Effective Revision
By proceeding you agree to create your account
Free CAT Formulae PDF will be sent to your email address soon !!!