All the numbers 411,752 and 1031 leaves same remainder 8 when divided by n.The value of n is

bhAI its 16 if but 1031 kk jgh 1032 hoga

411, 752, 1031 leave a remainder 8 when they are divided by n; So the numbers must be divisible by n when 8 is subtracted from each of them, i.e, 403, 744, 1023 must be divisible by n find out the highest common factor of 403, 744, 1023. H.C.F (403,744,1023) = 31