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10 months, 2 weeks ago
10 months, 2 weeks ago
Intial mixture = 125 gallons
% of water in mixture = 20
Thus, quantiity of water = 25 gallons
Let 'x' gallons of water be added to mixture so that new concerntration of water is 25%.
-> (25+x)/(125+x)=25/100
->100(25+x) = 25(125+x)
Solving above eqn, we get x = 25/3 or 8.33.
Thus 8.33 gallons water is required to increase concerntration of water from 20% to 25%.
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