A four-digit number gets reversed when it is multiplied by 4. find the sum of the digits of the number.

for hit and trial it will take time is there another method

Let the number be 'abcd'.
We can write as 1000a+100b+10c+d.
According to the question:
(1000a+100b+10c+d)x4=1000d+100c+10b+a
We get as 3999a+390b-60c-996d=0
Use hit and trial :
Take a=2,b=1,c=7,d=8.The above condition gets satisfied.
Now add the values of a,b,c,d.That will be your answer.
Answer:18