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10 months, 2 weeks ago
10 months, 1 week ago
Let the number be 'abcd'.
We can write as 1000a+100b+10c+d.
According to the question:
(1000a+100b+10c+d)x4=1000d+100c+10b+a
We get as 3999a+390b-60c-996d=0
Use hit and trial :
Take a=2,b=1,c=7,d=8.The above condition gets satisfied.
Now add the values of a,b,c,d.That will be your answer.
Answer:18
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