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3 years, 9 months ago
3 years, 9 months ago
6.3 days
let, the work in unit = lcm(10,12)=60
A = 60/10=6 unit/day , B = 60/12 =5unit/day
now as B left 2days earlier so , subtract 2days of work of B i.e. 2*5 =10 from 60
60-10 =50
this amount of work would be done by A and B together i.e. 50/5+6 =50/11 and remaining 10 units is done by A alone = 10/6
sum of both =50/11 +10/6 =6.33 approx
3 years, 9 months ago
10 and 12 LCM is 60 and if b leaves 2 days before so add b,s 2 days work so total days approx is 70/11= 6.36 days.
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