Question 95

The graphs of the equations $$2x + 3y = 11$$ and $$x - 2y + 12 = 0$$ intersects at $$P(x_1, y_1)$$ and the graph of the equations $$x - 2y + 12 = 0$$ intersects the x-axis at $$Q (x_2, y_2)$$. What is the value of $$(x_1 - x_2 + y_1 + y_2)$$?

Solution

$$2x + 3y = 11$$ ---(1)
$$x - 2y + 12 = 0$$
$$2x - 4y = -24$$ ---(2)
From eq (1) and (2),
7y = 35
y = 5 = $$y_1$$
From eq (1),
$$2x + 3 $$\times$$ 5 = 11$$
2x = -4
x = -2 = $$x_1$$
Now,
The graph of the equations $$x - 2y + 12 = 0$$ intersects the x-axis.
So,
$$ y = y_1$$ = 0
$$x - 0 + 12 = 0$$
x = -12 = $$x_1$$
$$(x_1 - x_2 + y_1 + y_2)$$
= -2 + 12 + 5 + 0 = 15


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