Question 94

From a point exactly midway between the foot of two towers P and Q,the angles of elevation of their tops are $$30^\circ$$ and $$60^\circ$$, respectively. The ratio of the height of P to that of Q is:

Solution

AO = OB
In $$\triangle AOP$$,
$$tan30\degree = \frac{AP}{AO}$$
$$\frac{1}{\sqrt{3}} = \frac{AP}{AO}$$
AP = 1
AO = $$\sqrt{3}$$

In $$\triangle AOP$$,
$$tan60\degree = \frac{BQ}{BO}$$
$$\frac{\sqrt{3}}{1} = \frac{BQ}{BO}$$
$$\frac{BQ}{BO} = \frac{3}{\sqrt{3}}$$
BQ = 3
BO = $$\sqrt{3}$$
The ratio of the height of P to that of Q = 1 : 3


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App