If 6A = 11B = 7C; find A : B : C
Let $$6A = 11B = 7C = k$$
=> $$A = \frac{k}{6}$$ , $$B = \frac{k}{11}$$ , $$C = \frac{k}{7}$$
=> Ratio of A : B : C = $$\frac{k}{6} : \frac{k}{11} : \frac{k}{7}$$
= $$\frac{1}{6}$$ : $$\frac{1}{11}$$ : $$\frac{1}{7}$$
L.C.M. of 6,11 and 7 = 462, thus multiplying by 462, we get :
= $$\frac{462}{6} : \frac{462}{11} : \frac{462}{7}$$
= 77 : 42 : 66
=> Ans - (B)
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