Question 93

If 6A = 11B = 7C; ﬁnd A : B : C

Solution

Let $$6A = 11B = 7C = k$$

=> $$A = \frac{k}{6}$$ , $$B = \frac{k}{11}$$ , $$C = \frac{k}{7}$$

=> Ratio of A : B : C = $$\frac{k}{6} : \frac{k}{11} : \frac{k}{7}$$

= $$\frac{1}{6}$$ : $$\frac{1}{11}$$ : $$\frac{1}{7}$$

L.C.M. of 6,11 and 7 = 462, thus multiplying by 462, we get :

= $$\frac{462}{6} : \frac{462}{11} : \frac{462}{7}$$

= 77 : 42 : 66

=> Ans - (B)

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: