Two students appeared for an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. The marks obtained by them are
Let marks scored by 1st student = $$x$$
=> Marks scored by another student = $$(x + 9)$$
According to question, => $$(x + 9) = \frac{56}{100} \times (x + x + 9)$$
=> $$x + 9 = \frac{14}{25} \times (2x + 9)$$
=> $$25x + 225 = 28x + 126$$
=> $$3x = 225 - 126 = 99$$
=> $$x = \frac{99}{3} = 33$$
$$\therefore$$ Marks scored by other student = 33 + 9 = 42
=> Ans - (C)
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