A quadratic equation : $$ax^2 + bx + c = 0$$ has equal roots iff Discriminant, $$D = b^2 - 4ac = 0$$
(A) :Â $$3x{2}-6x+2=0$$
=> D = $$(-6)^2 - 4(3)(2) = 36 - 24 = 12 \neq 0$$
(B) :Â $$3x^{2}-6x+3=0$$
=>Â D = $$(-6)^2 - 4(3)(3) = 36 - 36 = 0$$
(C) :Â $$x^{2}-8x+8=0$$
=> D = $$(-8)^2 - 4(1)(8) = 64 - 32 = 32 \neq 0$$
(D) :Â $$4x^{2}-8x+2=0$$
=>Â D = $$(-8)^2 - 4(4)(2) = 64 - 32 = 32 \neq 0$$
Thus, the equation :Â $$3x^{2}-6x+3=0$$ has equal roots.
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