If the 3rd and the 5th term of an arithmetic progression are 13 and 21, what is the 13th term?
$$T_{3}$$ = a + 2d = 13-------(1)
$$T_{5}$$ = a + 4d = 21-------(2)
on solving (1) AND (2)
d = 4 & a = 5
$$T_{13}$$ = a + 12d = 5 + 12(4) = 5 + 48 = 53
So the answer is option A.
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