Let the plane containing the line of intersection of the planes $$P_1: x + (\lambda + 4)y + z = 1$$ and $$P_2: 2x + y + z = 2$$ pass through the points $$(0, 1, 0)$$ and $$(1, 0, 1)$$. Then the distance of the point $$(2\lambda, \lambda, -\lambda)$$ from the plane $$P_2$$ is

A

5$$\sqrt{6}$$

B

4$$\sqrt{6}$$

C

2$$\sqrt{6}$$

D

3$$\sqrt{6}$$