Question 85

Two chords AB and CD of a circle with centre O intersect at P. If $$\angle APC$$ = $$40^\circ$$. Then the value of $$\angle AOC$$ + $$\angle BOD $$ is

Solution

Arc AC subtends $$\angle AOC$$ at the centre and $$\angle ABC$$ at the circumference.

Similarly ,

$$\angle BOD = 2\angleBCD$$

=$$\angle AOC + \angle BOD$$

=2($$\angle ABC + \angle BCD$$)

= 2 $$\angle APC = 2\times 40\degree = 80\degree$$

So, the answer would be option c)$$80^\circ$$

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