Question 85

If $$\frac{(1-sinA)}{(1+sinA)}=x$$, then x is

Solution

Expression : $$\frac{(1 - sinA)}{(1 + sinA)}$$

Multiplying both numerator and denominator by $$(1-sinA)$$

= $$\frac{(1 - sinA)}{(1 + sinA)}$$ $$\times \frac{(1-sinA)}{(1-sinA)}$$

= $$\frac{(1-sinA)^2}{1-sin^2A} = \frac{(1-sinA)^2}{cos^2A}$$

= $$(\frac{1-sinA}{cosA})^2 = (\frac{1}{cosA}-\frac{sinA}{cosA})^2$$

= $$(secA-tanA)^2$$

=> Ans - (C)

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