If $$\frac{(1-sinA)}{(1+sinA)}=x$$, then x is
Expression : $$\frac{(1 - sinA)}{(1 + sinA)}$$
Multiplying both numerator and denominator by $$(1-sinA)$$
=Â $$\frac{(1 - sinA)}{(1 + sinA)}$$ $$\times \frac{(1-sinA)}{(1-sinA)}$$
= $$\frac{(1-sinA)^2}{1-sin^2A} = \frac{(1-sinA)^2}{cos^2A}$$
= $$(\frac{1-sinA}{cosA})^2 = (\frac{1}{cosA}-\frac{sinA}{cosA})^2$$
= $$(secA-tanA)^2$$
=> Ans - (C)
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