Two people A and B are at a distance of 260 km from each other at 9:00 a.m. A immediately starts moving towards B at a speed of 25 km/h and at 11:00 a.m. B starts moving towards A at a speed of 10 km/hr. At what time (in p.m.) will they meet each other?

Speed of A = 25 km/hr and speed of B = 10 km/hr

Distance between A and B = 260 km

At 9:00 am, A starts moving, => distance covered by A in 2 (11-9) hours = $$25\times2=50$$ km

Distance left between A and B at 11:00 am = $$260-50=210$$ km

Now, at 11:00 am both move towards each other, => relative speed = $$25+10=35$$ km/hr

=> Time taken to meet each other = $$\frac{210}{35}=6$$ hours

$$\therefore$$ Time at which they will meet = 11:00 am + 6 hours = 5:00 pm

=> Ans - (A)