Question 83
A, B and C are three students. A got 18% more marks than B and 12% less than C. If B got 220 marks, then how much marks C has got?
Solution
B's marks = 220
A got 18% more marks than B
=> A's marks = $$220+(\frac{18}{100}\times220)=259.6$$
Also, A got 12% less marks than C
=> C's marks = $$259.6\times\frac{100}{(100-12)}$$
= $$\frac{25960}{88}=295$$
=> Ans - (B)
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