Question 82
A student multiplied a number by 3/10 instead of 10/3. What is the percentage error in the calculation?
Solution
Let the number be 30
When the student multiplied it by 3/10, => original result = $$\frac{3}{10} \times 30 = 9$$
When the student multiply it by 10/3, => New result = $$\frac{10}{3} \times 30 = 100$$
=> Percentage error in calculation = $$\frac{(100 - 9)}{100} \times 100$$
= $$\frac{9100}{100} = 91\%$$
=> Ans - (C)
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