Question 82

A student multiplied a number by 3/10 instead of 10/3. What is the percentage error in the calculation?

Solution

Let the number be 30

When the student multiplied it by 3/10, => original result = $$\frac{3}{10} \times 30 = 9$$

When the student multiply it by 10/3, => New result = $$\frac{10}{3} \times 30 = 100$$

=> Percentage error in calculation = $$\frac{(100 - 9)}{100} \times 100$$

= $$\frac{9100}{100} = 91\%$$

=> Ans - (C)

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