In 2004, the total monthly salary of A and B together was Rs, 18000. In 2005 monthly salary of A and B increased by 14% and 20% respectively from previous year. If after the given increment A’s salary became 76% of B’s salary. What was A’s salary in 2004 (that is before the mentioned increment of 2005) ?

Let A's salary in 2004 = $$Rs. 100x$$

=> B's salary in 2004 = $$Rs. (18,000 - 100x)$$

In 2005 monthly salary of A and B increased by 14% and 20% respectively.

=> A's salary in 2005 = $$100x + \frac{14}{100} \times 100x = 114x$$

B's salary in 2005 = $$(18,000 - 100x) + \frac{20}{100} \times (18,000 - 100x)$$

= $$(18,000 - 100x) + (3600 - 20x) = (21,600 - 120x)$$

Also, A’s salary became 76% of B’s salary.

=> $$114x = \frac{76}{100} \times (21,600 - 120x)$$

=> $$(21,600 - 120x) = 114x \times \frac{100}{76}$$

=> $$(21,600 - 120x) = 150x$$

=> $$150x + 120x = 270x = 21600$$

=> $$x = \frac{21600}{270} = 80$$

$$\therefore$$ A's salary in 2004 = $$100 \times 80 = Rs. 8,000$$