3 numbers whose average is 112, the first number is 1/6th the sum of other 2. What is the first number?
Let the three numbers be $$x,y,z$$
Sum of three numbers = $$x + y + z = 112 \times 3 = 336$$
According to ques, => $$x = \frac{1}{6} \times (y + z)$$
=> $$x = \frac{1}{6} \times (336 - x)$$
=> $$6x = 336 - x$$
=> $$6x + x = 7x =336$$
=> $$x = \frac{336}{7} = 48$$
=> Ans - (D)
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