The shortest distance between the lines $$\frac{x-5}{1} = \frac{y-2}{2} = \frac{z-4}{-3}$$ and $$\frac{x+3}{1} = \frac{y+5}{4} = \frac{z-1}{-5}$$ is

A

$$7\sqrt{3}$$

B

$$5\sqrt{3}$$

C

$$6\sqrt{3}$$

D

$$4\sqrt{3}$$