Surface area of a cuboid is 22 $$cm^2$$ and the sum of the lengths of all its edges is 24 cm. The length of each diagonal of the cuboid, in cm, is
Let length, breadth and height be $$l,b,h$$ cm respectively.
=> Surface area of cuboid = $$(lb+bh+hl)=281$$ -----------(i)
Sum of all edges = $$(l+b+h)=24$$
Squaring both sides, => $$(l^2+b^2+h^2)+2(lb+bh+hl)=576$$
Substituting value from equation (i), we get :
=> $$(l^2+b^2+h^2)+2(281)=576$$
=> $$(l^2+b^2+h^2)=576-562=14$$
$$\therefore$$ Diagonal of cuboid = $$\sqrt{l^2+b^2+h^2}=\sqrt{14}$$
=> Ans - (D)