Let $$S = \{\theta \in [0, 2\pi) : \tan(\pi\cos\theta) + \tan(\pi\sin\theta) = 0\}$$, then $$\sum_{\theta \in S} \sin^2\left(\theta + \frac{\pi}{4}\right)$$ is equal to

Name: Let S = \\\\{\\theta \\in [0, 2\\pi) : \\tan(\\pi\\cos\\theta) + \\tan(\\pi\\sin\\theta) = 0\\\\}, then \\sum_{\\theta \\in S} \\sin^2\\left(\\theta + \\frac{\\pi}{4}\\right) is equal to
Uploaded: 2026-06-01T21:21:16.340562+05:30
Duration: 2 min 36 s
Description: Let S = \\\\{\\theta \\in [0, 2\\pi) : \\tan(\\pi\\cos\\theta) + \\tan(\\pi\\sin\\theta) = 0\\\\}, then \\sum_{\\theta \\in S} \\sin^2\\left(\\theta + \\frac{\\pi}{4}\\right) is equal to

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Let $$S = \{\theta \in [0, 2\pi) : \tan(\pi\cos\theta) + \tan(\pi\sin\theta) = 0\}$$, then $$\sum_{\theta \in S} \sin^2\left(\theta + \frac{\pi}{4}\right)$$ is equal to

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