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100 families planned wedding on 21st December 2020 at 9 pm, an auspicious day and time in New Delhi and booked a marriage hall online in Chattarpur Farms. Due to a technical glitch the hall was booked simultaneously for 64 families who received a confirmation with a deposit of ₹ 1 Lakh each. The managementon identifying the glitch was troubled and contacted the families for a refund but the families were not ready to accommodate. The managementand the families then mutually agreed to have a toss in order to decide which family will be finally allotted the venue. Certain directions regarding holdingthe toss are as follows:
1. The families were allotted a number from 1 to 64 in alphabetical ascending order of their names.
2. It was further decided, Family 1 will have a toss with Family 64 andis considered as Toss 1. Toss 2 will be between Family 2 and Family 63 and Toss 3 between Family 3 and Family 62 and so on.
3. The winner of each toss moves to the next round and the winner of Toss 1 will now have a toss with winner of Toss 32, winner of Toss 2 with Toss 31 and so on.
4. The remaining rounds of toss are in ascending order i.e. winner of Toss 1 with Toss 2, winner of Toss 3 with Toss 4 and so till there is one winner.
5. It was also decided that if the final winner withdrawsand hands over the venue to the other finalist, the winner will be given ₹ 1.5 Lakh over and above the refund amount.
From the following, which family in descending order can have the toss with Family 12 in finals?
1. 62
2. 60
3. 63
4. 61
The below table shows the matching of families in each round as per the given conditions.
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Since 12 reaches the finals, we will trace its matches to see which family it replaces.
Round 1 against 53, round 2 against 21, round 3 against 11, round 4 against 9, round 5 against 13 and round 6 against 1. Thus, 12 replaces 9 in round 6.
Hence, the family facing it in the finals must replace 1 in the finals.
Since we have to calculate in descending order, let's first consider family 63.
63 plays round 1 against 2, round 2 against 31, round 3 against 1, round 4 against 3, round 5 against 5, and round 6 against 9.
Thus, 63 replaces 1 in the final round and can face 12.
Since we have to find the family in descending order and 63 satisfies the condition, the answer is option C.
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