Question 78
What is the area (in sq cm) of a rectangle if its diagonal is 51 cm and one of its sides is 24 cm?
Solution
Breadth = $$b=24$$ cm and Diagonal = $$d=51$$ cm
=> Length of rectangle = $$l=\sqrt{d^2-b^2}$$
= $$\sqrt{(51)^2-(24)^2}=\sqrt{2601-576}$$
= $$\sqrt{2025}=45$$ cm
$$\therefore$$ Area of rectangle = $$lb$$
= $$45 \times 24=1080$$ $$cm^2$$
=> Ans - (C)
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