One of the diagonal of a rhombus is 70% of the other diagonal. What is the ratio of area of rhombus to the square whose side is same as the length of the larger diagonal?
Let larger diagonal of the rhombus = side of square = $$10x$$
=> Smaller diagonal = $$\frac{70}{100}\times10x=7x$$
=> Ratio of area of rhombus to area of square
= $$\frac{\frac{1}{2}d_1d_2}{a^2}$$
= $$\frac{1}{2}\times(\frac{10x\times7x}{10x\times10x})$$
= $$\frac{1}{2}\times\frac{7}{10}=\frac{7}{20}$$
=> Ans - (C)
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