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8 years, 6 months ago
8 years, 6 months ago
Hi Shweta,
That's the best way to solve this problem.
7777 mod 74 is 7
So, one 7 is carried over as remainder for the first four 7s. After that, one 7 is carried over as remainder for every three 7s (because of the carried over 7 acting as the fourth 7)
78 is a multiple of 3
So, there will be one carry-over 7 after the first seventy-nine 7s.
So, the expression becomes 77 mod 74 = 3
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