Let $$y = y(x)$$ be the solution of the differential equation $$\frac{dy}{dx} = (y+1)\left((y+1)e^{x^2/2} - x\right)$$, $$0 < x < 2.1$$, with $$y(2) = 0$$. Then the value of $$\frac{dy}{dx}$$ at $$x = 1$$ is equal to

A

$$\frac{-e^{3/2}}{(e^2+1)^2}$$

B

$$-\frac{2e^2}{(1+e^2)^2}$$

C

$$\frac{e^{5/2}}{(1+e^2)^2}$$

D

$$\frac{5e^{1/2}}{(e^2+1)^2}$$