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Question 74
Two students, A and B, appeared for an examination. A secured 8 marks more than B and the marks of the former was 60% of the sum of their marks. The sum of the marks obtained by A and B is:
Solution
given that marks scored by A= 8+B
also given that former has scored 60% of total score
$$A=\frac{60}{100}(A+B)$$
$$A=\frac{6}{10}(A+B)$$
10A = 6A + 6B
4A = 2B
But , A = 8 + b (given)
4(B + 8) = 6B
B = 16
A = 16 + 8 = 24
sum of the marks obtained by A and B is 24+16=40
hence answer is C
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