Question 74

The area of a quadrant of a circle is $$\frac{\pi}{9}$$ m$$^2$$. Its radius (in metres) is equal to:

Solution

Let the radius of the circle = r

Area of the quadrant of the circle = $$\frac{\pi}{9}$$ m$$^2$$

$$\frac{1}{4}\times\pi$$r$$^2$$ = $$\frac{\pi}{9}$$

r$$^2$$ = $$\frac{4}{9}$$

r = $$\frac{2}{3}$$

Radius of the circle = $$\frac{2}{3}$$ m

Hence, the correct answer is Option A

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