Question 74
The area of a quadrant of a circle is $$\frac{\pi}{9}$$ m$$^2$$. Its radius (in metres) is equal to:
Solution
Let the radius of the circle = r
Area of the quadrant of the circle = $$\frac{\pi}{9}$$ m$$^2$$
$$\frac{1}{4}\times\pi$$r$$^2$$ = $$\frac{\pi}{9}$$
r$$^2$$ = $$\frac{4}{9}$$
r = $$\frac{2}{3}$$
Radius of the circle = $$\frac{2}{3}$$ m
Hence, the correct answer is Option A
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