Ramu works 4 times as fast as Somu. If Somu can complete a work in 20 days independently, then the number of days in which Ramu and Somu together can complete the work is:
Number of days required for Somu to complete work = 20 days
Ramu works 4 times as fast as Somu
$$=$$> Number of days required for Ramu to complete work = $$\frac{20}{4}=5$$ days
Let the Total Work = W
Work done by Ramu in 1 day =Â $$\frac{W}{5}$$
Work done by Somu in 1 day =Â $$\frac{W}{20}$$
Work done by Ramu and Somu in 1 day =Â $$\frac{W}{5}+\frac{W}{20}=\frac{5W}{20}=\frac{W}{4}$$
Number of days required for both Ramu and Somu together to complete work =Â $$\frac{W}{\frac{W}{4}}=4$$ days
Hence, the correct answer is Option A
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