Tap A can fill a tank in 6 hours and tap B can empty the same tank in 10 hours. If both taps are opened together, then how much time (in hours) will be taken to fill the tank?

Let the Volume of the tank = $$V$$

Given,

Tap A can fill the tank in 6 hours

$$=$$>  Volume filled by Tap A in 1 hour = $$\frac{V}{6}$$

Tap B can empty the tank in 10 hours

$$=$$>  Volume emptied by Tap B in 1 hour = $$\frac{V}{10}$$

$$=$$>  Volume filled by both the taps in 1 hour = $$\frac{V}{6}-\frac{V}{10}=\frac{5V-3V}{30}=\frac{V}{15}$$

$$\therefore\ $$Number of hours required for both the taps to fill the tank = $$\frac{V}{\frac{V}{15}}=15$$ hours

Hence, the correct answer is Option B