Let $$f(x) = \begin{cases} -a & \text{if } -a \leq x \leq 0 \\ x + a & \text{if } 0 < x \leq a \end{cases}$$ where $$a > 0$$ and $$g(x) = (f(x|) - |f(x)|)/2$$. Then the function $$g : [-a, a] \rightarrow [-a, a]$$ is :

$$(g(x)=\frac{f(x)-|f(x)|}{2})$$

$$If(f(x)<0\Rightarrow g(x)=f(x)=-a)$$

$$If(f(x)>0\Rightarrow g(x)=0)$$

So range = ({-a, 0})

→ Not one-one, not onto

Neither one-one nor onto

Create a FREE account and get:

Predict your JEE Main percentile, rank & performance in seconds

Check Your Score Now

Ask our AI anything

AI can make mistakes. Please verify important information.

Download resources