Bar graph shows the number of males and females in five organizations A, B, C, D and E.

For which organisation, difference between the number of males and the average number of females of all the organisations is minimum?

The average number of females in all the organisations = $$\frac{300+275+250+200+125}{5}$$ = $$\frac{1150}{5}$$ = 230

For Organisation A, difference between the number of males and the average number of females of all the organisations = 250 - 230 = 20

For Organisation B, difference between the number of males and the average number of females of all the organisations = 230 - 225 = 5

For Organisation C, difference between the number of males and the average number of females of all the organisations = 325 - 230 = 95

For Organisation D, difference between the number of males and the average number of females of all the organisations = 275 - 230 = 45

$$\therefore$$  For Organisation B, difference between the number of males and the average number of females of all the organisations is minimum.

Hence, the correct answer is Option D