The difference between simple and compound interest (compounded annually) on a sum of money for 3 years at 10% per annum is Rs. 93. The sum (in Rs.) is:

Let the given sum = Rs. $$1000x$$

Rate of interest = 10% and time period = 3 years

Compound interest = $$P [(1 + \frac{R}{100})^T - 1]$$

= $$1000x [(1 + \frac{10}{100})^3 - 1]$$

= $$1000x [(\frac{11}{10})^3 - 1] = 1000x (\frac{1331 - 1000}{1000})$$

= $$1000x \times \frac{331}{1000} = 331x$$

Simple interest = $$\frac{P \times R \times T}{100}$$

= $$\frac{1000x \times 10 \times 3}{100} = 300x$$

=> Difference between simple and compound interests = $$331-300x = 93$$

=> $$31x = 93$$

=> $$x = \frac{93}{31} = 3$$

$$\therefore$$ Value of given sum = $$1000 \times 3 = Rs. 3,000$$