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If $$(x+7954\times7956)$$ be a square number, then the value of x is
$$(x+7954\times7956)$$
= [x+(7955-1)(7955+1)]
= [x+$$7955^{2}$$-1]
to become a perfect square, x-1 = 0 so x = 1.
so the answer is option A.
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