The volume of a right circular cone is equal to the volume of that right circular cylinder whose height is 48 cm and diameter of its base is 20 cm.If the height of the cone is 16 cm, then what will be the diameter of its base?

Given, Height of the cylinder = 48 cm
Diameter of the cylinder = 20 cm
Then, Radius of the cylinder = 10 cm
Volume of the cylinder = $$\pi \times 10^2 \times 48 cm^3$$
Given, Height of the cone = 16 cm
Let the radius of the cone = r cm
Volume of the cone = $$\dfrac{1}{3}\times \pi r^2 \times 16 cm^3$$
Given, Volume of the cone = Volume of the cylinder
$$\dfrac{1}{3}\times \pi r^2 \times 16 = \pi \times 10^2 \times 48$$

=> $$r^2 = 10^2 \times 3^2$$
=> $$r = 10\times3 = 30 cm$$
Therefore, Diameter of the base of the cone = 2*30 = 60 cm.