Let $$f(x) = ax^2 + bx + c$$ be such that $$f(1) = 3, f(-2) = \lambda$$ and $$f(3) = 4$$. If $$f(0) + f(1) + f(-2) + f(3) = 14$$, then $$\lambda$$ is equal to

A

-4

B

$$\frac{13}{2}$$

C

$$\frac{23}{2}$$

D

4