A player has a certain average for 15 innings. In the 16th inning he scores 120, there by his average increases by 6 runs. What is the new average?

Let the average of the player after 15 innings = $$x$$

$$=$$>  Sum of the scores of the player after 15 innings = $$15x$$

In the 16th inning he scored 120,

$$=$$>  Sum of the scores of the player after 16 innings = $$15x+120$$

Given, average of the player after 16 innings = $$x+6$$

$$=$$>  $$\frac{15x+120}{16}=x+6$$

$$=$$>  $$15x+120=16\left(x+6\right)$$

$$=$$>  $$15x+120=16x+96$$

$$=$$>  $$x=24$$

$$\therefore\ $$New average after 16 innings = $$x+6=24+6=30$$

Hence, the correct answer is Option B