What least number must be added to 1039, so that the sum obtained is completely divisible by 29?
Factorizing 1039 = 29 $$\times$$ 35 + 24
Thus, on dividing 1039 by 29, the remainder is 24
$$\therefore$$ The number that must be added to 1039 so that the sum obtained is completely divisible by 29
= 29 - 24 = 5
=> Ans - (B)
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