Two students appeared for an examination. One of them secured 13 marks more than the other and his marks were 76% of the sum of their marks. The marks obtained by them are
Let marks scored by 1st student = $$x$$
=> Marks scored by another student = $$(x + 13)$$
According to question, => $$(x + 13) = \frac{76}{100} \times (x + x + 13)$$
=> $$x + 13 = \frac{19}{25} \times (2x + 13)$$
=> $$25x + 325 = 38x + 247$$
=> $$38x - 25x = 325 - 247 = 78$$
=> $$x = \frac{78}{13} = 6$$
$$\therefore$$ Marks scored by other student = 6 + 13 = 19
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