Question 67

In an examination, A obtained 10% more marks than B, B obtained 20% more marks than C and C obtained 32% less marks than D. If A obtained 272 more marks than C, then the marks obtained by B is:

Solution

let the D obtained 100% marks.

Marks of C =

Marks of C = 100% $$\times \frac{68}{100}$$ = 68%

Marks of B = 68% $$\times \frac{120}{100} $$= 81.6%

Marks of A = 81.6% $$\times \frac{110}{100}$$ = 89.76%

Difference of the marks of A and C = 272

89.76% - 68% = 272

21.76% = 272

81.6% = $$\frac{272}{21.76} \times 81.6$$ = 1020

Marks obtained by B = 1020

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