Question 66

The compound interest on ₹20,000 at 5% per annum, compounded annually, is ₹2,050. What is the time period?

Solution

compound interest = CI = ₹2,050

principal amount = P = ₹20,000

rate of interest = R = 5%

time period = T

$$CI=P\left[\left(1+\frac{R}{100}\right)^T-1\right]$$

$$2050=20000\left[\left(1+\frac{5}{100}\right)^T-1\right]$$

$$2050=20000\left[\left(1+\frac{1}{20}\right)^T-1\right]$$

$$41=400\left[\left(\frac{21}{20}\right)^T-1\right]$$

$$\frac{41}{400}=\left[\left(\frac{21}{20}\right)^T-1\right]$$

$$\frac{41}{400}+1=\left(\frac{21}{20}\right)^T$$

$$\frac{441}{400}=\left(\frac{21}{20}\right)^T$$

$$\left(\frac{21}{20}\right)^2=(\frac{21}{20})^T$$
T = 2

So the time period is 2 years.


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