Question 66

The Bar graph given below presents the amount (volume in litres) of water in ten different mixtures.

The amount of water in mixture M3 is what percent of amount of water in mixture M6?

Solution

The amount of water in mixture M3 = 15

The amount of water in mixture M6 = 24

so,

= $$\frac{M3}{M4}\times100$$

= $$\frac{15}{24}\times100$$

= 62.5%

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