Height of a right circular cone is 8 cm. If diameter of its base is 12 cm, then what will be the curved surface area of the cone?
Given, Diameter of the base of the cone = 12 cm
Then, Radius = 6 cm
Given, Height of the cone = 8 cm
Slant height of the cone = $$\sqrt{\text{Radius}^2+\text{Height}^2} = \sqrt{6^2+8^2} = \sqrt{36+64} = \sqrt{100} = 10 cm$$
Curved Surface area of the cone = $$\pi rL = \dfrac{22}{7} \times 6 \times 10 = \dfrac{1320}{7} cm^2$$
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