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Three machines A, B and C working together can do a work in x hours. When working alone, A needs an additional 6 hours to do the work; B, one additional hour and C, x additional hours. The value of x is
Time taken by the machines working together = $$x$$ hours
According to ques,
=> $$\frac{1}{x+6}+\frac{1}{x+1}+\frac{1}{x+x}=\frac{1}{x}$$
=> $$\frac{(x+6)+(x+1)}{(x+6)(x+1)}=\frac{1}{x}-\frac{1}{2x}$$
=> $$\frac{2x+7}{(x+6)(x+1)}=\frac{1}{2x}$$
=> $$4x^2+14x=x^2+7x+6$$
=> $$3x^2+7x-6=0$$
=> $$3x^2+9x-2x-6=0$$
=> $$(3x-2)(x+3)=0$$
=> $$x=\frac{2}{3},-3$$
$$\because$$ $$x$$ cannot be negative, hence $$x=\frac{2}{3}$$ hours
=> Ans - (A)
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