If the numerator of a fraction is increased by 15% and denominator is decreased by 20%, then the fraction, so obtained, is $$\frac{17}{65}$$ What is the original fraction?

Let the numerator of the fraction = $$x$$

Denominator of the fraction = $$y$$

Numerator when increased by 15% = $$\frac{115}{100}x$$

Denominator when decreased by 20% = $$\frac{80}{100}y$$

Given, new fraction = $$\frac{17}{65}$$

$$=$$>  $$\frac{\frac{115}{100}x}{\frac{80}{100}y}=\frac{17}{65}$$

$$=$$>  $$\frac{115x}{80y}=\frac{17}{65}$$

$$=$$>  $$\frac{x}{y}=\frac{17\times80}{65\times115}$$

$$=$$>  $$\frac{x}{y}=\frac{272}{1495}$$

$$\therefore$$The original fraction $$=\frac{x}{y}=\frac{272}{1495}$$

Hence, the correct answer is Option A