If the maximum distance of normal to the ellipse $$\dfrac{x^2}{4} + \dfrac{y^2}{b^2} = 1, b < 2$$, from the origin is 1, then the eccentricity of the ellipse is:

A

$$\dfrac{1}{\sqrt{2}}$$

B

$$\dfrac{\sqrt{3}}{2}$$

C

$$\dfrac{1}{2}$$

D

$$\dfrac{\sqrt{3}}{4}$$